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2020-08-21T07:41:39Z

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== Usage ==
Performs a calculation.

<nowiki>{{</nowiki>#invoke:{{BASEPAGENAME}}|''add''|5|8}}

=== Examples ===

<code><nowiki>{{#invoke:Sandbox/Lemondoge/Calc|add|3|6}}</nowiki></code> returns {{#invoke:Sandbox/Lemondoge/Calc|add|3|6}}

<code><nowiki>{{#invoke:Sandbox/Lemondoge/Calc|minus|6|3}}</nowiki></code> returns {{#invoke:Sandbox/Lemondoge/Calc|minus|6|3}}

<code><nowiki>{{#invoke:Sandbox/Lemondoge/Calc|mod|3|15}}</nowiki></code> returns {{#invoke:Sandbox/Lemondoge/Calc|mod|3|15}}

== Error detection ==

The "times" function (but not the VERY similar "multiplication" function) will return a error like this: "{{#invoke:Sandbox/Lemondoge/Calc|times|0|0|0}}", if the second parameter is 0, unless the third parameter is set to 1. This works by using the code below.
<syntaxhighlight lang="lua">
if num2 == 0 and errordetect ~= 1 then
return RError("You cannot multiply a number by zero.")
else
return num1 * num2
end
</syntaxhighlight>

== Anti-not-a-number mechanism ==
The "division" function (and it's similar "div" function) will normally return "{{#invoke:Sandbox/Lemondoge/Calc|div|0|0|0}}" if all 3 parameters are set to 0, but if the third parameter is 1, it will return "{{#invoke:Sandbox/Lemondoge/Calc|div|0|0|1}}" instead. This works with the code below:
<syntaxhighlight lang="lua">
if num1 == 0 and num2 == 0 and antinotanumber == 1 then
return 1
else
return num1 / num2
end
</syntaxhighlight>
<includeonly>{{#ifeq:{{SUBPAGENAME}}|sandbox | |


}}</includeonly>

Module:Sandbox/Lemondoge/Calc/doc - Revision history

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